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Earn +20 ptsQ: 81 1 9 49 9 2 64 4?
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What rule is in this pattern 100 81 64 49?
It is the squares in decreasing order from 102: 100 = 102 81 = 92 64 = 82 49 = 72 etc So it will continue with 62, 52, 42, ... The nth term is given by tn = (11 - n)2
What is the pattern of 36 49 64 81?
The simplest pattern that your teacher is most likely to want is: U{n} = (n + 5)² for n = 1, 2, 3, 4 ie each term is the square of the next whole number starting with 6: {36, 49, 64, 81} = {6², 7², 8², 9²}
How do i factorise 49(m 2n)2 81(2m n)2?
Distribute the 49 and 81 first
What are the first ten square numbers?
# 1^2=1 # 2^2=4 # 3^2=9 # 4^2=16 # 5^2=25 # 6^2=36 # 7^2=49 # 8^2=64 # 9^2=81 # 10^2=100
What are all he numbers from 1 to 300 that are perfect square numbers?
They are: 1 1^2 4 2^2 9 3^2 16 4^2 25 etc. 36 49 64 81 100 121 144 169 196 225 256 289 17^2
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