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∙ 8y ago
Nabeel Gulzar
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What is the square of n squared plus 2n minus 1?
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
How do you add n squared plus n squared?
n2 + n2 = 2 n2
What is n2 in math?
n x n = n2
What is the trinomial of n2 -3n plus 2?
n2-3n+2
How do you balance ag plus n2 equals ag3n?
6AG + N2 --> 2AG3N is the balanced equation.
How do you balance N2 plus O2 equals N2 O5?
3H2 + N2 --> 2NH3This is the Haber process which makes ammonia (NH3)
Could you Balance NH4NO3 - N2 O2 H2O?
2NH4NO3->2N2+O2+4H2O
What is the balance to N2 plus O2 equals NO?
The balance is 2N2 +2O2= 4NO
Can you add 2n2-n plus 5 and n2 plus 1?
Yes I can.
What is the factor or 2n2 plus 6n minus108?
2(n2+3n-54) 2(n+9)(n-6)
What is the answer to the sum of the squares of two consecutive positive integers is 3785 find the two integers?
The integers are 43 and 44. The answer can be found by representing the two consecutive numbers as "n" and "n+1". n2 + (n+1)2 = 3785 n2 + (n2 + 2n + 1) = 3785 2n2 + 2n + 1 = 3785 2n2 + 2n - 3784 = 0 n2 + n - 1892 = 0 (n + 44) (n-43) = 0 n = -44, +43 The answer is restricted to positive values, so n = 43 and n+1 = 44
How do you work out the nth term of 1 - 5 - 13?
The sequence is too short to be certain but it could be tn = (n-1)2 + n2 = 2n2 -2n + 1
How can you balance NH4NO2 yields N2 H2O?
2nh4no3 ---> 2n2 + o2 + 4h2o
What is the chemical equation for the combustion of nitrogen?
The general equation for complete combustion of nh4no3 is actually the equation for the thermal decomposition of ammonium nitrate. It is: 2NH4NO3 ---> 2N2(g) + 4H2O(l)+ O2(g).
What do you know about the sums and the product of odd and even numbers?
Even numbers : they can be written 2n 2n1+2n2+....+2nm = 2(n1+n2+....+nm) so it's always an even number 2n1x 2n2x....x2nm = 2(n1+n2+....+nm) which is always an even number Odd numbers: they canbe written 2n+1 (2n1+1) + (2n2+1) + ....+ (2nm +1) = 2(n1+n2+....+nm) + m which is even if m is even and odd if m is odd, so it depend of the number of terms (2n1+1) x (2n2+1) x ....x (2nm +1) is always odd cause the last term of the expansion is always +1 and other terms have at least 2 as factor
Can 9 odd numbers make 50?
An odd number is written 2n+1 with n any number (2n1+1)+(2n2+1)+...+(2n9+1) = 2(n1+n2+...+n9)+9 = 50 is not possible as 2(n1+n2+...+n9) = 41 is not possible with integers
The sum of the squares of the two larger of three consecutive even integers is 12 less than 4 times the square of the smaller one. Find the integers?
Let lowest number be n. The larger numbers are n + 2 and n + 4. So 4n2 = (n + 2)2 + (n + 4)2 + 12 = n2 + 4n + 4 + n2 + 8n + 16 + 12 = 2n2 + 12n + 32 So 4n2 - 2n2 - 12n - 32 = 0 ie 2n2 - 12n -32 = 0 which factorises as (2n - 16)(n + 2) The positive solution is thus n = 16/2 = 8 and the other numbers are 10 & 12.
