5t - 7 = 11 5t - 7 + 7 = 11 + 7 5t = 18 5t/5 = 18/5 t = 18/5 t = 3 3/5
5t + rt = t(5+r)
5t is5t is5t is5t is
5t^2 - 25t - 10 = 0 Looks like a quadratic formula problem, and it might be ugly. The discriminant, by simple visual inspection, tells me this has two real roots. Let us divide through by 5 to simplify things t^2 - 5t - 2 = 0 different parabola, but crosses X axis at same place t = -b +/- sqrt(b^2-4ac)/2a a = 1 b = -5 c = -2 -(-5) +/- sqrt[(-5)^2 - 4(1)(-2)]/2(1) 5 +/- sqrt(17)/2 ugly, but true
between 4 and 5.it is 4.47
5t + 2 = 3t - 2t + 5 Collect like terms 5t - 3t + 2t = 5 - 2 4t = 3 t = ¾ Check: 5 x 3/4 = 3¾ + 2 = 5¾; 3x¾- 2x¾ + 5 = 5¾ QED
That's entirely correct.If you divide each side of the equation by 't',you reach the startling conclusion that 5 = 5 !
5
2t^2+5t-3=0 (2t-1)(t+3)=0 2t-1=0 and t+3=0 t=.5 and t=-3
13
8t + 5 = 6t + 1,subtract 6t an 5 from each side,2t = -4t = -2Checking, 8t + 5 = -16 + 5 = -11 and 6t +1 = -12 + 1 = -11
8t^2 - 11t - 4
I'm going to assume that you mean 5t = 3t - 10. You solve for t in the following way. First combine like terms by subtracting 3t from both sides of the equation: 5t - 3t = 3t - 3t - 10, 2t = -10. Next, isolate t by dividing both sides of the equation by 2: 2t/2 = -10/2, t = -5. To verify that this is the solution, plug this value of t back into the original equation: 5(-5) = 3(-5) - 10, -25 = -15 - 10, -25 = -25. Since -25 does in fact equal -25, our value for t is correct.
-8+5T=-6 add 8 to each side 5T =8-6 5T=2 T=2/5 or T=0.4
5t - 1 = -11 Therefore, 5t = -10 t = -10/5 t = -2
Depends on which question you're asking: 1) (5t-5)/-10=70 5t-5=-700 5t=-695 t=-139 2) (5(t-5))/-10=70 5(t-5)=-700 5t-25=-700 5t=-675 t=-135
9t + 5 = 7 - 2t Subtract five from both sides: 9t = 2 - 2t Add 2t to both sides: 11t = 2 Divide both sides by 2 t = 2/11 or about .1818