5t^2 - 25t - 10 = 0
Looks like a quadratic formula problem, and it might be ugly. The discriminant, by simple visual inspection, tells me this has two real roots.
Let us divide through by 5 to simplify things
t^2 - 5t - 2 = 0
different parabola, but crosses X axis at same place
t = -b +/- sqrt(b^2-4ac)/2a
a = 1
b = -5
c = -2
-(-5) +/- sqrt[(-5)^2 - 4(1)(-2)]/2(1)
5 +/- sqrt(17)/2
ugly, but true
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5t - 7 = 11 5t - 7 + 7 = 11 + 7 5t = 18 5t/5 = 18/5 t = 18/5 t = 3 3/5
5t
5t + rt = t(5+r)
5t - 26 = 18tSubtract 5t from each side:-26 = 13tDivide each side by 13:-2 = t
5t is5t is5t is5t is