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5t^2 - 25t - 10 = 0

Looks like a quadratic formula problem, and it might be ugly. The discriminant, by simple visual inspection, tells me this has two real roots.

Let us divide through by 5 to simplify things

t^2 - 5t - 2 = 0

different parabola, but crosses X axis at same place

t = -b +/- sqrt(b^2-4ac)/2a

a = 1

b = -5

c = -2

-(-5) +/- sqrt[(-5)^2 - 4(1)(-2)]/2(1)

5 +/- sqrt(17)/2

ugly, but true

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14y ago

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Q: What is the answer for 5t square minus 25t minus 10?
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