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The sum of two numbers is 92 their difference is 20 find the numbers?
Let the two numbers be m and n From the information given, we have two equation in two unknowns. We can solve this system using substitution. Here are the two equations. m+n=92 m-n=20 Now to use substitution, we must rewrite the second equation as m=n+20 and substitute it into the first n+n+20=92 or 2n=72 which tells us n=36 that means m=92-36 or 56. So the numbers are 36 and 56. Let's check 36+56=92 56-36=20
How do you complete this number pattern in 2 possible ways 1 2 4?
Some, out of infinitely many possible ways, are: 1, 2, 4, 10 : U(n) = (n^3 - 5*n^2 + 10*n - 4)/2 for n = 1, 2, 3, 4 1, 2, 4, 9 : U(n) = (2*n^3 - 9*n^2 + 19*n - 6)/6 for n = 1, 2, 3, 4 1, 2, 4, 8 : U(n) = (3*n^3 - 3*n^2 + 8*n)/6 for n = 1, 2, 3, 4 1, 2, 4, 8 : U(1) = 1, U(n+1) = 2*U(n) for n = 1, 2, 3, 4 Note that the last two are the same sequence but with entirely different rules.
What is the pattern for 64 -16 4 -1?
U(1) = 64U(n+1) = -U(N)/4
What is the missing number 60 48 ............... 24?
Any number can be the missing number.If you want:1: then try the rule: U(n) = (35*n^3 - 245*n^2 + 466*n - 136)/22: then try the rule U(n) = 17n^3 - 119*n^2 + 226*n - 643: then try the rule: U(n) = (33*n^3 - 231*n^2 + 438*n - 120)/24: then try the rule U(n) = 16n^3 - 112*n^2 + 212*n - 56and so on.Having said that, the simplest linear rule is U(n) = 72 - 12n, which gives 36 as the missing number.
What is the missing number in the nuclear reaction 233 92 U-- 4 2 He?
229 apex
