5 and 4/9
63x/49 = 9x/7
9x^(2) - 49 Re-write as two squared terms. (3x)^(2) - 7^(2) This will factor to ( 3x - 7)(3x + 7) Note the two different signs.
X = 7 9x - 2x = 49
X = 7 9x - 2x = 49
(9x2 + 7)(9x2 - 7) = 81x4 - 49
This polynomial is irreducible; it cannot be factored.
the new problem would be 9(7)-2(7) when you substitute 7 for x.The answer is 63-14= 49 So your answer is 49(:
9x is the lowest common multiple. (9x * 1 = 9x) (x * 9 = 9x)
(9x)2 +9x/(45x)2 +81= 9+9x/86
9x - 8 = 46 9x = 46 +8 9x= 54 9x/9 = 54/9 x= 6
9x+6=51 9x = 45 x= 5 9x-6=51 9x = 57 x= 6.33
9x = 30