Total marbles in the bag = 10
Number of red ones = 3
Probability of pulling a red one on the first draw = 3/10 = 0.3
Total marbles remaining after the first draw = 9
Number of green ones = 5
Probability of pulling a green one after a red one has been withdrawn = 5/9
Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.
The probability is 0.56
5:16
There are a total of 25 Marbles The chances are 3 out of 25 drawing a Red marble. 3/25 = 12% chance of drawing a red marble
3/5
1
The probability of selecting 4 red marbles or 5 blue marbles depends on how many marbles there are altogether, and how many of the total number of marbles are red and how many are blue.
25/50 gives the probability of selecting a blue marble
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
2/6
The probability is 0.3692
Since the box contains 16 marbles, seven of them white, then the probability of drawing one white marble is 7/16. If you replace the marble and draw again, the probability of drawing another white marble is still 7/16. The net probability of drawing two white marbles, while replacing the first, is 49/256.
The probability of selecting a red marble is 3/9
There is a probability of 3 that it will be blue.
The probability of drawing two reds, with replacement, is the same as the probability of drawing a red, times itself. So: P(drawing two reds) = P(drawing a red)2 = (12/(2 + 12 + 6))2 = (12/20)2 = (3/5)2 = 9/25
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
It is 15/50 = 0.3
5/10