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Total marbles in the bag = 10

Number of red ones = 3

Probability of pulling a red one on the first draw = 3/10 = 0.3

Total marbles remaining after the first draw = 9

Number of green ones = 5

Probability of pulling a green one after a red one has been withdrawn = 5/9

Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.

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Q: A bag contains 3 red marbles 2 blue marbles and 5 green marbles What is the probability of selecting a red marble without replacing it in the bag and then selecting a green marble?
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