1
The probability is 0.56
The probability of pulling a red or yellow marble out of a bag of 3 green 8 red 8 yellow and 3 black marbles is 16 out of 22, or about 0.73.
There are at least 11 green marbles in the bag.
Total marbles in the bag = 10Number of red ones = 3Probability of pulling a red one on the first draw = 3/10 = 0.3Total marbles remaining after the first draw = 9Number of green ones = 5Probability of pulling a green one after a red one has been withdrawn = 5/9Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.
hypergeom. f(1;13,3,1) * f(1;12,5,1)
5/10
yes
Probability = number_of_white_marbles / total_number_of_marbles = 10 / (4 + 6 + 4 + 10) = 10 / 24 = 5/12 ~= 0.42
Total number of marbles in the bag = 6 + 19 + 5 + 19 + 17 = 66Number of yellow ones = 19If drawing perfectly randomly, then the probability of pulling a yellow one = 19/66 = 28.8% (rounded)
It depends on how many yellow-green marbles there are, and on how many total marbles there are. There is insufficient information in the question to answer it. Please restate the question, giving this other information.
0No blue marbles in the bag.
If you pull 35 marbles without replacement, the answer is 1: the event is a certainty. If you pull only one marble, at random, the probability is 16/50 = 8/25.
25
The probability is 0.56
The probability of pulling a red or yellow marble out of a bag of 3 green 8 red 8 yellow and 3 black marbles is 16 out of 22, or about 0.73.
There are at least 11 green marbles in the bag.
A bag contains 2 red marbles, 5 blue marbles, and 4 green marbles. What is the probability that a green marble will be chosen at random.