Well, honey, if you're reaching into that bag three times and each time you're pulling out a yellow marble and then putting it back in, the probability of picking a yellow marble each time is 8/21. Multiply that by itself three times because you're picking three marbles, and you get a probability of 512/9261. So, good luck with those yellow marbles, darlin'!
11 marbles total and 6 are blue so probability is 6/11
There is a one in 2 chance of getting a green marble.
The probability of picking the #1 marble on the first draw is 1/12. If you've done that, then the probability of picking the #2 marble on the second draw is 1/11. If you've done that, then, the probability of picking the #3 marble on the third draw is 1/10. If you've done that, then, the probability of picking the #4 marble on the fourth draw is 1/11. etc. etc. So the probability of doing all of them in sequence is (1/12) x (1/11) x . . . x (1/1). That's exactly the reciprocal of (12!). According to my $1.49 calculator, your chances of success without peeking amount to about 0.00000020877 percent (rounded) Not a smart bet.
7/12
Well, Collin has a 10p coin and three other coins that don't matter in this scenario. So, the probability of him randomly picking the 10p coin is 1 out of 4, which simplifies to 25%. Good luck to Collin and his lucky coin!
The probability of picking a green marble from a box that only contains blue marbles is zero.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
0No blue marbles in the bag.
None, if all the marbles that you have are yellow!
3/10 or 0.3 is the probability of picking a purple marble.
1 in 15 chances that the marble will be blue, because there are 15 marbles all together in a bag, and you are only picking one out of it.
The answer depends on how many marbles are picked and on whether or not they are returned to the jar before picking the next one. Since you have not bothered to provide any information on either of these aspects, I cannot provide a more useful answer.
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
Well, honey, there are 11 marbles in total, and 4 of them are blue. So, if you don't want a blue marble, that leaves you with 7 marbles to choose from. The probability of picking a marble that is not blue is 7/11. Hope that helps, sugar!
11 marbles total and 6 are blue so probability is 6/11
1/6Because:There is a 4 in 9 chance of picking a red ball the first time and 3 in 8 chance of picking a red ball the second time. The chance of picking two reds as the first two balls is 4/9 x 3/8 or 12/72 or 1/6
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D