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None, if all the marbles that you have are yellow!

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10y ago

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In a bag of marbles you have three green two yellow six blue and nine red marbles. What is the probability of picking a red marble from the bag?

To find the probability of picking a red marble, first determine the total number of marbles in the bag, which is 3 (green) + 2 (yellow) + 6 (blue) + 9 (red) = 20 marbles. The number of red marbles is 9. Therefore, the probability of picking a red marble is the number of red marbles divided by the total number of marbles, which is 9/20 or 0.45.


What is the probability of picking a blue marble from a bag of 4 red marbles 6 blue marbles and 1 white marble?

11 marbles total and 6 are blue so probability is 6/11


There is a bag of marbles 10 are red 15 are purple and 25 are yellow what is the probability of picking a purple marble?

3/10 or 0.3 is the probability of picking a purple marble.


If you have 6 red marbles 3 yellow marbles and 5 green marbles in a bag what is the probability of picking a blue marble out?

0No blue marbles in the bag.


A bag contains 3 red marbles 5 blue marbles 8 yellow marbles and 4 black marbles what is the theoretical probability of randomly picking each color marble?

The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.


If there are 3 red 4 blue and 5 yellow marbles what is the probability of pulling a red or blue marble vs the probability of pulling a red marble the first time and a blue marble the second time?

Pr(Red or Blue) = 0.5833...Pr(R on first pull and Blue on second pull) = 0.0533...


Suppose you choose a marble from a bag with 3 red 3 white and 5 blue You return the first marble to the bag and then choose again find P Red then Blue Can anyone help me with this math question?

To find the probability of drawing a red marble first and then a blue marble, we first calculate the probability of each event separately. The probability of drawing a red marble is ( \frac{3}{11} ), since there are 3 red marbles out of a total of 11 marbles. After returning the red marble, the probability of then drawing a blue marble is ( \frac{5}{11} ). Therefore, the combined probability of drawing a red marble first and then a blue marble is ( \frac{3}{11} \times \frac{5}{11} = \frac{15}{121} ).


What is the probability of choosing a marble that is not blue in problem 2?

if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble


A bag contains 6 red marbles 4 blue marbles and 1 green marble What is the probability of choosing a marble that is not blue?

Well, honey, there are 11 marbles in total, and 4 of them are blue. So, if you don't want a blue marble, that leaves you with 7 marbles to choose from. The probability of picking a marble that is not blue is 7/11. Hope that helps, sugar!


12 red marbles and 15 marbles are blue. if one marble is drawn from the bag What is the probabilitythe marble is not be red?

15/27. Simply take the probability of drawing a blue marble.


What is the probability of choosing a red marble from a jar 5 red 6 green and 4 blue marble?

1/3 or 33%


If you have three marbles red white and blue what is the probability that you do not get a white or blue marble?

1 in 3