Study guides

☆☆

Q: A cardboard box has a length of 3 feet height of 2½ feet and depth of 2 feet If the length and depth are doubled by what percent does the volume of the box change?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:

If the base stays the same, the area is also doubled.

When you change the linear size it changes the areas by the square and the volume of the cube.

As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.

volume is related as radius squared x height soif both radius and height doubled volume increases 2 x 2 x 2 = 8 times

Related questions

300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:

The volume will be doubled.

If the base stays the same, the area is also doubled.

A box of those dimensions would have a volume of 3 x 2 x 2 or 12 cubic feet. If the length is doubled to 6 feet, the depth is doubled to 4 feet and the height remains the same at 2 feet, the volume would then be: 6 x 4 x 2 or 48 cubic feet. The percent change of the increase would be the difference in the volumes, divided by the original volume, multiplied by 100. In this example, the percent increase is 36/12 times 100 or 300%.

The area of the triangle would double

if length and width are doubled then the volume should mulitiply by 8

It is quadrupled.

its volume is also doubled...

The area is multiplied by 4, not doubled.

When you change the linear size it changes the areas by the square and the volume of the cube.

As area_of_parallelogram = base x height if they are both doubled then: new_area = (2 x base) x (2 x height) = 4 x (base x height) = 4 x area_of_parallelogram Thus, if the base and height of a parallelogram are [both] doubled, the area is quadrupled.

The area gets doubled.

People also asked