360 degrees are in a circle no matter how big or small the circle is A circle has 360 degrees.
For A+ 7.22The area of a sector of a circle is proportional to the angle at the center of the sector, with 360 degrees corresponding to the full circle. Therefore, the area of the total circle for which the problem is stated is 50 X 360/110 = about 163.6 square units. The area of a circle is also equal to pi multiplied by the square of the radius of the circle, so that the radius r of this circle equals the square root of 163.6/pi = about 7.217 units. The circumference of the circle is also twice the radius multiplied by pi = 45 units, to the justified number of significant digits (limited by "50").a+ 45.33
Suppose the radius of the circle is r units and the sector subtends an agle of x radians at the centre of the circle. ThenArea = 0.5*r2*x square units.If x is measured in degrees, this becomesArea = pi*r2*x/360 square units.
360° subtends the complete circle of length 2πr. So, the ratio of 85/360 = A/2πr.......where A is the arc length A/26π = 85/360 A = 85 x 26π/360 = 19.286 units.
Area of the circle = pi*82 = 201.0619298 square units Area of the sector = 290/360 of 201.0619298 = 161.9665546 or about 162 square units
A circle's circumference has 360 degrees around it.
A circle has 360 degrees, whatever its diameter.
The circumference will have 360 degrees. So the arc is 94/360 of the whole circle. That is, the whole circle will be 360/94 of the arc length. So the circumference of the shole circle is 19.68*360/94 = 75.37 units (to 2 dp)
90*360/81 = 400 units of length.
If you mean a sector with an arc of 110 degrees and an area of 50 square units Area of all the circle: 360/110 times 50 = 163.'63' square units Radius of the circle is the square root of 163.'63'/pi = 7.2171377402 So the radius of the circle is about 7 units
360 degrees are in a circle no matter how big or small the circle is A circle has 360 degrees.
There are 360 degrees in a circle so it will be 1/3 of pi*62 square units
For A+ 7.22The area of a sector of a circle is proportional to the angle at the center of the sector, with 360 degrees corresponding to the full circle. Therefore, the area of the total circle for which the problem is stated is 50 X 360/110 = about 163.6 square units. The area of a circle is also equal to pi multiplied by the square of the radius of the circle, so that the radius r of this circle equals the square root of 163.6/pi = about 7.217 units. The circumference of the circle is also twice the radius multiplied by pi = 45 units, to the justified number of significant digits (limited by "50").a+ 45.33
Area of the circle = pi*7.8752 = 194.8278319 square units Area of sector = 75/360 times 194.8278319 = 40.58913165 square units
360 degrees = Total number, T. So a sector of x degrees is equivalent to x*T/360 units.
240 deg gives a sector area of 10 sq units so 360 deg would give a sector area of 10*360/240 = 15 sq units ie the area of the whole circle is 15 sq units or π*r2 = 15 so that r = 2.1851 units (to 4 dp)
They are both units in the measure of an angle. There are 360 degrees in a full turn of a circle. There are 2 pi (radian measure) in a full turn of a circle.