Let c represent the number of chickens and p represent the number of pigs.
Since chickens and pigs have one head each, 70 heads = c + p.
Since chickens have 2 legs and pigs have 4 legs, 200 legs = 2c + 4p.
Subtracting twice the first equation (140 = 2c + 2p) from the second, we get
60 = 2p
or
p = 30 pigs
Rewriting the first equation as c = 70 - p, we get c = 40 chickens.
chickens chickens
Heads: P + C = 24C = 24 - PLegs: 4P + 2C = 80Substitute, from heads: 4P + 2 (24 - P) = 804P + 48 - 2P = 802P = 32P = 16C = 24-P = 8====================Check:P + C = 16 + 8 = 244P + 2C = 4(16) + 2(8) = 64 + 16 = 80 yay!
C+P=26 2C+4P=70 Therefore C=26-P Therefore 2(26-P)+4P=70 Therefore 52-2P+4P=70 Therefore 52+2P=70 Therefore 2P=18 Therefore P=9 Therefore C+9=26 Therefore C=17 There are 17 chickens.
Take P to be the number of pigs and C to be the number of chickens. Because both anamals have a head, the sum of C and P is 143, or C + P = 143 Because a chicken contributes 2 legs and a pig contributes 4, C times 2 plus P times 4 equals the total number of legs, or 2C + 4P = 478 divide this equation by 2 to get C +2P = 239 Subtract the first equation from this one P = 96 plug this into the first equation C + 96 = 143 C = 47 96 Pigs and 47 chickens
Chickens have two legs . Hence 9 x 2 = 18 Dogs have four legs ; Hence 2 x 4 = 8 Cats also have four legs ; hence 4 x 3 = 12 18 + 8 + 12 = 40 Hence answer is TRUE!!!!!!
The farmer saw two cows and two chickens. Each cow has one head, four legs, and one tail, and each chicken has one head, two legs, and one tail.
7 cows and 11 chickens. Cows have 4 legs. Chickens have 2 legs. (4 legs)(7 cows) + (2 legs)(11 chickens) = 50 legs. 7 cow heads = 11 chicken heads = 18 heads.
Assuming that all of the animals are "normal" (no amputees, 2-headed mutations, etc.) : 15 cows (15 x 4 = 60 legs) plus 5 chickens (5 x 2 = 10 legs) gives a total of 20 heads and 70 legs.
Suppose there are x chickens and y cows Then heads => x + y = 64 And Legs => 2x + 3y = 147 2*Heads: 2x +2y = 128 Subtract from Legs: 19 = y Substitute in Heads: x = 45 Answer: 45 chickens.
On a farm there are chickens and three-legged-cows. There are total of 49 heads and 130 legs. How many chickens are on the farm?
chickens chickens
There are 5 chickens and 6 pigs in the barn. Each chicken has 2 legs and each pig has 4 legs.
85 chickens
There are 42 chickens in the farm.
there are 36 horses and 23 chickens.........
Let x = the number of goats (4 legs) 4x = the number of chickens (2 legs) So we have 4*x + 2*4x = 144 4x + 8x = 144 12x = 144 x = 144/12 = 12 (goats and 48 chickens) or Let's suppose that each of them have 6 legs, so there would be 24 chickens and goats (144/6), and we can say there are 12 chickens and 12 goats. But the number of chickens is 4 times the number of goats, so there are 48 chickens (4*12) and 12 goats.
48 chickens 1 pig