Points are (1,3) and (5,4) so the slope is the rise/ run= 4-3/5-1 =1/4
The points will form a right angle triangle in a circle whose hypotenuse is its diameterLength from (8, 5) to (5, 1) = 5Midpoint: (6.5, 3) which is the centre of the circleRadius: 2.5Equation of the circle: (x-6.5)^2+(y-3)^2 = 6.25
If you're asking a question, then the answer is 'no'. If you're making a statement, then the statement is false. I can always lay a single plane down on any three points you choose. If your points are in the same straight line, then there an infinite number of other planes that your points all lie in. If they're not all in the same straight line, then there's only one plane.
cuz it just is
You haven't given points, you've just given single values. for there to be a point in a plane, you need 2 coordinates, both x and y
There are 4
points of co-ordinates plane are represent by cartesian
It has centre (0, 0) and radius 5.
points of co-ordinates plane are represent by cartesian
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
It describes points on a plane.
They are the coordinates of x and y to plot out straight lines or curves on the Cartesian plane
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
From the given information and using the appropriate formulae the area of the circle works out as 65*pi square units.
Yes when the straight line passes through the origin (0, 0) on the Cartesian plane it has no y intercept.
It is: y = -2.5x+7
On the Cartesian plane points have coordinates of length and height
Rise = (-1 - 4) = -5 Run = (2 - -2) = 4 Slope = Rise/Run = -5/4 = -20