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Not always because it could be less than 0 as for example -3 because an integer is a whole number without decimals or fractions

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Q: A n integer is greater than 0?
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Is it true that the square of a number is greater than the number itself?

It depends on what you mean by a number. If n is a positive integer (except for 1), then n^2 is greater than n. If n = 0 or 1, then n and n^2 are equal. If n = 1/2, then n is greater than its square. If n is negative, then n is always less than its square.


If N is a nonzero integer then n plus 1 divided by n is always greater than 1?

2


What is a rectangular number 93 120 301?

A rectangular number is any number greater than or equal to 2, that is the product of an positive integer n multiplied by the integer that comes before it. So 2x1 for example or 5x4 or 10x111. If you look at the number 93120301=n(n+1), this number is rectangular if n^2+n-93120301=0 has a solution that is a positive integer. There is no integer solution so that number is not rectangular. How about 93? n^2+n-93=0 also has no solution in the natural numbers.


Why must the product of any two numbers greater than 1 be a composite number?

A composite number is a positive integer which has a positive divisor other than one or itself. In other words, if 0 < n is an integer and there are integers 1 < a, b < n such that n = a × b then n is composite. By definition, every integer greater than one is either a prime number or a composite number. The number one is a unit - it is neither prime nor composite. For example, the integer 14 is a composite number because it can be factored as 2 × 7.


What are the equivalent fraction of 16 over 20?

Take any integer, n, greater than 1.Then 16*n/(20*n) will be an equivalent fraction.

Related questions

Is it true that the square of a number is greater than the number itself?

It depends on what you mean by a number. If n is a positive integer (except for 1), then n^2 is greater than n. If n = 0 or 1, then n and n^2 are equal. If n = 1/2, then n is greater than its square. If n is negative, then n is always less than its square.


Why are decimal numbers not integers?

For simplicity I will assume you're working in base x, for any integer x greater than 1, although the argument extends to integers greater than 1 in absolute value (note that in base -1,1 all decimal numbers are in fact integers and that in base 0 decimals are not very well defined). In base x, x can of course be conveniently denoted as 10, so in the remainder of this answer I will work in base x. It is sufficient to show that there exists a decimal number that is not an integer so take 0.1 or 10^-1. This number has the property that 10*0.1 = 1, it is the multiplicative inverse of 10. I will now prove by induction that no positive integer has this property. Base case: 1*10 = 10 which is greater than 1 by assumption. Suppose n*10 is greater than 1, then (n+1)*10 = n*10+1*10 = n*10 + 10 which is still greater than 1. So we now know that n*10 is always greater than 1 for any n greater than 0, from which it can be deduced that for these n, n*10 is also unequal to -1. Therefore, for no integer n unequal to zero can n*10 be 1. Now assume n=0, then n*10 = 0*10 = 0 which is not equal to 1 either. Thus, no integer n has the property n*10=1, whereas the decimal number 0.1 does. So 0.1 is not an integer and therefore the decimal numbers are not integers.


If N is a nonzero integer then n plus 1 divided by n is always greater than 1?

2


What is a rectangular number 93 120 301?

A rectangular number is any number greater than or equal to 2, that is the product of an positive integer n multiplied by the integer that comes before it. So 2x1 for example or 5x4 or 10x111. If you look at the number 93120301=n(n+1), this number is rectangular if n^2+n-93120301=0 has a solution that is a positive integer. There is no integer solution so that number is not rectangular. How about 93? n^2+n-93=0 also has no solution in the natural numbers.


Why must the product of any two numbers greater than 1 be a composite number?

A composite number is a positive integer which has a positive divisor other than one or itself. In other words, if 0 < n is an integer and there are integers 1 < a, b < n such that n = a × b then n is composite. By definition, every integer greater than one is either a prime number or a composite number. The number one is a unit - it is neither prime nor composite. For example, the integer 14 is a composite number because it can be factored as 2 × 7.


How many polygon do we have?

Infinitely many. For each integer n (greater than 2), there is a polygon with n sides or n vertices.


What is the sum of any integer n and zero?

The sum of any integer ( n ) and zero is ( n ).


What is 101 as a fraction renamed to a mixed number?

101 is a whole number and so it makes hardly any sense to rename it as a mixed number, but, if you were really keen to do it, you could write it as 101 0/n, where n is any integer greater than 0.


What is the number that no value of can be greater than for the solutions to the equation in fermats last theorem?

Fermat's last theorem states that the equation xn + yn = zn has no integer solutions for x, y and z when the integer n is greater than 2. When n=2, we obtain the Pythagoras theorem.


What fraction is equivalent to 13 over 14?

Pick any integer n, greater than 1. Then (n*13)/(n*14) is an equivalent fraction.


What are the equivalent fraction of 16 over 20?

Take any integer, n, greater than 1.Then 16*n/(20*n) will be an equivalent fraction.


What are two equivalent fractions for 2 7ths?

Take any integer, n, greater than 1.Then (2*n)/(7*n) will be an equivalent fraction.