Yes, by definition.
The sum of zero and a negative integer can never be zero - it will always be negative and nonzero. Although zero is also an integer, it is neither negative nor positive and cannot be the other integer used.
There is none, because there is always a greater integer.
No, not always. For example: 55 divided by 5 is 11. 55 divided by 10 is 5.5. It will divide, but not to an integer.
Let N be any non-zero integer. Then 58*N divided by N will always give 58 as their quotient.
Yes, it is.
Yes.
Yes, always. That is the definition of a rational number.
Yes, by definition.
Because that is how a rational number is defined!
I had this name question for homework :| no
Because that is how a rational number is defined!
If ( p ) is an integer and ( q ) is a nonzero integer, then the expression ( \frac{p}{q} ) will always yield a rational number. Additionally, since ( q ) is nonzero, ( p ) cannot be divided by zero, ensuring the division is valid. Furthermore, ( p + q ) will also be an integer, as the sum of two integers is always an integer.
A rational number is always the result of dividing an integer when the divisor is nonzero.
No.
The opposite of a nonzero integer is found by changing its sign. For example, if you have a nonzero integer like +5, its opposite is -5. This relationship holds for any nonzero integer; the opposite will always be the same number with an inverted sign. Thus, the opposite of a nonzero integer ( x ) is simply ( -x ).
Yes.