being 8 squares and 72 sq. ft. Then the 8 squares can be arrange as a 4 x 2 polygon.
Each of the 8 squares has an area of 72 / 8 = 9 sq.ft.
Hence any one side of the square is 9^(1/2) = 3 ft.
Hence length one one is 4 x 3 = 12 ft.
Length the other way is 2 x 3 = 6 ft
The two sides of the perimeter are 12 ft and 6 ft.
Hence it follows that the foursides of the perimeter are
12 + 12 + 6 + 6 = 36 ft.
NB You are incorrect when described the area as '72 ft', this is a LENGTH not an AREA. . It it 72 sq. ft. ( an AREA)
Isosceles trapezoids, squares, and rectangles.
Yes, if the perimeters are the same, then both of them have side = perimeter / 4. And of course the angles are all 90°, since they are squares.
What solid figure has congruent squares on all six sides
They can be.
Some are regular and some are not . Regular rectangles are called squares. A square is a regular polygon because all of it's sides and angles are congruent. Oblong rectangles do not have all their sides congruent and so are not regular.
Yes they are
Isosceles trapezoids, squares, and rectangles.
Yes, if the perimeters are the same, then both of them have side = perimeter / 4. And of course the angles are all 90°, since they are squares.
A polygon in which all sides and all angles are congruent is called a regular polygon. Examples include equilateral triangles, squares, and regular pentagons. In a regular polygon, each exterior angle is equal, and the interior angles are also equal, contributing to its symmetrical properties. The number of sides determines the specific type of regular polygon.
Yes, a square with a side of 2 cm is congruent to a square with a perimeter of 8 cm. The perimeter of a square is calculated as 4 times the length of one side. In this case, a square with a perimeter of 8 cm has a side length of 8 cm ÷ 4 = 2 cm, making both squares identical in size and thus congruent.
No, a rectangle that is 30 inches long and 10 inches wide cannot be divided into two congruent squares. The largest square that can fit within the rectangle would have a side length of 10 inches, resulting in only one square, not two. Therefore, it is not possible to create two congruent squares from this rectangle.
Yes into 10 inches by 10 inches squares
Yes, because it is made of congruent squares or equal squares.
No. Most squares probably are not congruent. Although they are similar.
It depends on the type of squares your looking at, if the are exactly the same its congruent.
can it for a trapezoid?
It's possible for any polygon with an even number of sides to have 2 pairs of congruent and parallel sides.Every parallelogram, including all rhombera, rectangles, and squares, must have.