Anything to the power of 0 is 1 (except 0 for some strange reason), so yes.(a+b)0= 1
3(a+b)0= 3
(3a+3b)0= 1
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Yes.
If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
The zero of a polynomial in the variable x, is a value of x for which the polynomial is zero. It is a value where the graph of the polynomial intersects the x-axis.
If x^2 is second degree, and x (which is x^1) is first degree, then a constant would be zeroth degree, I think since x^0 = 1 for any non-zero x.
Well, honey, a polynomial equation can have multiple solutions, depending on the degree of the polynomial. A polynomial of degree "n" can have at most "n" solutions, including complex solutions. So buckle up and solve those equations, darlin'!