A rectangle is 3 times long as it is wide if its perimeter is 56cm find the width of the rectangle?

Answer 1

Oh, dude, it's like this: if the rectangle is 3 times longer than it is wide, we can call the width "W" and the length "3W." The perimeter of a rectangle is the sum of all its sides, so for this one, it's 2W + 2(3W) = 56cm. Just solve for W, and you'll find the width of the rectangle. Easy peasy!

Answer 2

Let's denote the width of the rectangle as "w" and the length as "3w". The perimeter of a rectangle is calculated by adding all four sides, so in this case it would be 2w + 2(3w) = 56. Simplifying the equation gives 8w = 56, and thus the width of the rectangle would be w = 7 cm.

Answer 3

Oh, isn't that just a happy little problem we have here? To find the width of the rectangle, we first need to set up an equation based on the information given. Since the rectangle is 3 times as long as it is wide, we can let the width be "w" and the length be "3w". The perimeter of a rectangle is calculated by adding up all the sides, so we can write the equation as 2w + 2(3w) = 56cm. By solving this equation, we can find the width of the rectangle.

Answer 4

Well, well, well, aren't we getting fancy with our rectangles? If the perimeter is 56cm, that means the sum of all sides is 56cm. Since a rectangle has two pairs of equal sides, if the width is x, then the length is 3x. So, 2x + 2(3x) = 56cm. Solve that equation, and you'll find the width of the rectangle.

Answer 5

Suppose the width is W cm.

Then the length is 3W cm.

THerefore, the perimeter is 2*(3W + W) = 8W = 56

So W = 7 cm.