If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.
4hr.
You would need four recorders. The total time you could potentially record then would be six hours.
same
This would be 6.5 hours.
If 7 pipes can fill a water tank in 6 hours, then 1 pipe would take 7 times 6 or 42 hours. Take 42 and divide by 9, and you get 4 2/3 hours. That is the time it would take for 9 pipes to fill the tank.
The number of scaffolding pipes required would depend on the dimensions of each pipe and the design of the scaffolding structure. To calculate the exact number of pipes needed to construct 1000 cubic meters of scaffolding, you would need to know the length, width, and height of the scaffolding, as well as the spacing and configuration of the pipes.
If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.
They would dig a hole called a Latrine. When it was not needed any more it was filled in with dirt.
One-fifth of the tank
If we didn't have water pipes I would be out of a job. Water pipes are needed for delivery of the water to a specific place and that is done using pressure and flow using pumps or gravity. Most residential houses don't have domestic water pipes bigger then 1" in size. Almost all water pipes outside of a building are buried in the ground. Every time you turn on a faucet (if on city water) then you could be using water from a water tank many miles away.
If helping the poor and dying were popular at the time, Mother Teresa would not have needed to do the things she did. She filled a niche that was not being filled by others.
Close t 6000 gal.
So that they would have all that they needed for a journey to the afterlife
You would need 0.05 hours to reach 8 hours from 7.95 hours. This is equivalent to 3 minutes.
A plumber might use math to measure and calculate the area of pipes or the amount of space needed for an installation. Plumbers also would need math to calculate the amount of fluid need to go through pipes at the desired temperatures, pressures, and sizes of pipes.
It would take a day (24 hours).