Q: One pipe can fill a pool in 12 hours while a second pipe can fill the same pool in half the time How long would it take to fill the pool if both pipes are used?

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10 2/7 hours

If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.

The number varies (commonly, redheads have somewhat fewer hairs, while blonds have more), but the number of hairs on your head is roughly 100,000. If you count non-stop, one per second, it would take you 27.78 hours.

it depends on how fast you count. If you count one number every second it would take 300,000 seconds which is 5000 minutes or 83 hours if you can stay awake that long. If you count ten numbers a second that is about 8.3 hours

1 million seconds = 277.777778 hours At 8 hours per day = 34.72222225 days.

Related questions

If 7 pipes can fill a water tank in 6 hours, then 1 pipe would take 7 times 6 or 42 hours. Take 42 and divide by 9, and you get 4 2/3 hours. That is the time it would take for 9 pipes to fill the tank.

10 2/7 hours

If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.

It would burn out the pump motor after a while. I don't recommend doing it.

At what speed - 70mph would be a journey of just over 9 hours, while at 55mph, it would take over 11.6 hours !

Copper pipes are very durable and most advised.

The keyboard instrument with pipes would be the humble pipe organ.

how many second in a hour and how many hours in a day

0.28 hours or about 16.7 minutes.

You could install your own sewer cam and get a look however doing so would likely involve getting in to your sewer pipes which is best left to a professional. Call a plumber to look in to your pipes if he can't find anything install the cam while he's got the pipes open.

Firstly the noise is caused by rattling pipes which havent been secured down properly. secondly having low pressure after a while would indicate either air in the lines or your water pipes have started to clog up somewhere

Less conductive I would say.