1^3 + 2^3 = 1 + 8 = 9
2^3 + 1^3 = 8 + 1 = 9
There is also:
1^3 + (-1 + i√3)^3 = 9
1^3 + (-1 - i√3)^3 = 9
(-1/2 + i√3/2)^3 + 2^3 = 9
(-1/2 - i√3/2)^3 + 2^3 = 9
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Yes. It doesn't matter if you add zeros on to the end. That won't change the value of the number. Sometimes it is helpful to do that when you want place holders, for example if you are adding a group of decimal numbers and you want to keep them lined up so you add them correctly.
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Maths answers can be found on various websites. Google the topic which you want to find.
-- Start out with 40 identical cubes. -- Take 8 of them. Place them on the table in 2 rows, 4 cubes in each row, without any spaces between them. -- Take four more groups of 8 cubes. On other places on the table, arrange each group in 2 rows of 4 in each row, just like you did the first group. -- Pile all five groups up on top of each other, neatly, in one pile of five layers. Pile them carefully, so that all the sides of the pile are flat, straight, and smooth. There should be no holes in the pile, and you should have no cubes left over. The pile of five layers is the rectangular prism you want.
Presumably they should be all the correct answers.