Let's work that out together.
X + 10 = 34 so 34 - 10 = X so 34 - 10 = 24
Elga is X so is 24.
57
A = E - 9 A + E = 87 that is, (E - 9) + E = 87 2E - 9 = 87 2E = 87 + 9 = 96 E = 96/2 = 48
11 and 12
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
26
If Alvin is 7 years younger than Elga, then Alvin + 7 = Elga. If the sum of their ages is 87, then Alvin + Elga = 87. Substitute Alvin + 7 in the previous equation to get Alvin + (Alvin + 7) = 87. Reduce that and get 2 Alvin = 80 which means that Alvin = 40. That means that Elga = 47.
It is 50 years.
57
Let's represent Elga's age as x. Since Alvin's age is three times Elga's age, we can represent Alvin's age as 3x. The sum of their ages is 76, so we can create an equation: x + 3x = 76. Combining like terms, we get 4x = 76. Dividing both sides by 4, we find x = 19. Therefore, Elga's age is 19 years old.
Alvin +Elga = 56 3 : 1 56 ÷ 4 = 14 Alvin = 56 - 14 = 42 Elga = 14
Elga is 24, because this would mean that Alvin's age is 48, and 24+48=72.
A = E - 9 A + E = 87 that is, (E - 9) + E = 87 2E - 9 = 87 2E = 87 + 9 = 96 E = 96/2 = 48
Alvin is 44 and Benjamin is 11.
28
JFK had three brothers. Joseph was 2 years older, Robert was 8 years younger and Edward (Ted) was 15 years younger. By the time JFK was president, Joseph was already deceased.
11 and 12
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.