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s = ut + ½at²

s = distance = height of apple before it fell

u = 0 m/s (initial speed of apple)

t = 1.75 s (time of movement)

a = acceleration = g (acceleration due to gravity)

→ s = ½g1.75² = 1.53125g m

taking g as approx 9.81 m/s²

s ≈ 1.53125 × 9.81 m ≈ 15 m

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7y ago
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7y ago

It was 15 metres high.

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Q: An apple falls out of a tree and takes 1.75 seconds to strike the ground. How high was the apple from the ground?
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