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The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 91 ft in 2 seconds how far will it have fallen?
Wiki User
∙ 7y ago
The answer is 91 ft, of course!
Wiki User
∙ 7y ago
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What is the distance traversed by the particle between 0 seconds and 6 seconds?
The distance, expressed in inches, is(1.2) x (the particle's average speed, in feet per minute) .
Why is the slop on a distance time graph speed?
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What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
What happens to parallax as the distance to a star increases?
In that case, the parallax will decrease. It is inversely proportional. The relationship is the following:parallax (in arc-seconds) = 1 / distance (in parsec) In fact, that's how the parsec is defined.
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The duration of Falling Skies is 2700.0 seconds.
How far does something fall in 2.56 seconds?
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
How do you describe the relationship between distance and square of time?
If you're talking about romantic relationships: distance + time = 0If you're talking about physics, then your question may relate to acceleration, where acceleration = distance over time squared. Speed increases incrementally, so acceleration equals such additional speed over so many seconds. If speed is distance over time then acceleration is distance over time over time or, put another way, distance over time squared.Another way of figuring this is by focusing on the distance.Distance is directly proportional to time for a moving body.Looking at the relationship of distance, square of time and acceleration, we may consider falling objects and gravity.Gravitational acceleration is speed = gravity x time squared. For every second of freefall an object accelerated 9.8 m per second. So, given the figures at hand, we have 9.8 meters per second squared.Somehow or other I'm sure all of these things are a metaphor for what happens in a long-distance relationship. Either way, one is looking at the continual acceleration of something falling until it hits bottom.
What is the distance a free falling body travels from rest in ten seconds?
d = 0.5 * g * t2d = (0.5) * (9.8 m/s2) * (10 s)2 = 490 m
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Multiply by a value in seconds, that way you find out the distance. The distance will be in metres which will be travelled in a certain amount of seconds
What is the speed in ms of the object after falling 0.5 seconds?
4.9
The distance s meters traveled by a falling body starting from rest after time t seconds is?
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
