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True.

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It was false

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It was false bro I got a 60 π

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Im a sophomore :) from Texas thatβs is a idiot looking for answers online

Q: An equation for a line in the plane allows you to find the x- and y-coordinates of any point on that line?

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The origin (0,0,0) is not on the plane.

Rigidity.

A binormal plane is the straight line passing through a point M0 of a curve L perpendicular to the oscillating plane to L at M0. If r=r(t) is a parameterization of L, then the vector equation of the binormal at M0 corresponding to the value of t0 to the parameter of t has the form.

What is used to locate a point in a coordinate plane

The set of all points in the plane equidistant from one point in the plane is named a parabola.

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Yes if it is a straight line equation

True

The origin (0,0,0) is not on the plane.

To graph the set of all the solutions to an equation in two variables, means to draw a curve on a plane, such that each solution to the equation is a point on the curve, and each point on the curve is a solution to the equation. The simplest curve is a straight line.

By plotting the coordinates of a straight line equation.

Rigidity.

Yes if it is a straight line equation

The x and y coordinates

It is a linear equation in two variables, x and y. Any point on the line defined by the equation will satisfy the equation and conversely, any ordered pair that satisfies the equation will represent a point, in the Cartesian plane, will be on the line.

No, it will not, this is because a plane mirror has no focal point. It's rays never converge at a single point like a concave mirror, and therefore it has no focal point The mirror equation is 1/f=1/di + 1/do, where f is the focal point, di is the distance of the image from the mirror, and do is the distance of the reflected object from the mirror. Since focal point is required for the equation, it can't work. Hope this helps.

Yes, I'm confident of that.

In 3 dimensional graphing, a plane is a 2 dimensional solution to an equation. In other terms, a plane is all lines parallel to each other where one point on each line is colinear with one point on each line. Associate point:0d, line:1d, plane:2d.