Yes if it is a straight line equation
Yes, I'm confident of that.
coordinates.
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The coordinates will be at the point of the turn the parabola which is its vertex.
-5
To determine what plane point P is on, we need additional information such as the coordinates of point P and the equations or defining characteristics of the planes in question. A point lies on a plane if it satisfies the plane's equation. If you provide the coordinates of point P and the equations of the planes, I can help identify which plane it belongs to.
Yes if it is a straight line equation
By plotting the coordinates of a straight line equation.
True
To find the distance from a point to a plane, you can use the formula ( d = \frac{|Ax_0 + By_0 + Cz_0 + D|}{\sqrt{A^2 + B^2 + C^2}} ), where ( Ax + By + Cz + D = 0 ) is the equation of the plane, and ( (x_0, y_0, z_0) ) are the coordinates of the point. This formula calculates the perpendicular distance from the point to the plane by substituting the point's coordinates into the plane's equation and normalizing it by the plane's normal vector's magnitude.
True.
In coordinate geometry, each point in the plane is identified by an ordered pair, (x,y) which are known as the coordinates of the point. The equation of any straight line in the coordinate plane can be written in the form y = mx + c so that the coordinates of each point on the line satisfies this equation (and the coordinates of a point outside the line doed not satisfies it). The equation in this form is known as the slope-intercept form. m is the slope and c is the intercept.
Yes, I'm confident of that.
is an equation of a line in plane coordinate geometry. The coordinates of every point on that line satisfy the equation so there are an infinite number of solutions to the equation.
Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
coordinates
Its coordinates!