The first six positive integer multiples of 216 are: 1 x 216 = 216 2 x 216 = 432 3 x 216 = 648 4 x 216 = 864 5 x 216 = 1080 6 x 216 = 1296
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
The cubed root of 216 is 6. 6 x 6 x 6 = 216
Alright, sweetheart, buckle up. The multiples for 5 are 5, 10, 15, 20, 25, 30, and so on. For 6, we've got 6, 12, 18, 24, 30, 36, and the list goes on. Now go forth and conquer those multiples, champ.
It is equivalent to the equation: 6m = 216
216 and 6216 are two.
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
The first six positive integer multiples of 216 are: 1 x 216 = 216 2 x 216 = 432 3 x 216 = 648 4 x 216 = 864 5 x 216 = 1080 6 x 216 = 1296
72, 144, 216 and so on.
72, 144, 216 and so on.
72, 144, 216, 288, 360, 432
5 multiples of:5: 5, 10, 15, 20, 256: 6, 12, 18, 24, 30
24, 48, 72, 96, 120, 144, 168, 192, 216, 240
The total number of integers that are multiples of both 6 and 8 is infinite. Here are the first few: 24, 48, 72, 96, 120, 144, 168, 192, 216, 240 . . .
Let the second of the three consecutive multiples of 6 be 6n Then the first is 6n - 6 and the last is 6n + 6; and: (6n - 6) + 6n + (6n + 6) = 666 → 18n = 666 → n = 37 → the consecutive multiples of 6 which sum to 666 are 216, 222, 228
There are an infinite amount of multiples of 6, thus that cannot be answered. The first 5 are: 6, 12, 18, 24, 30. Some other examples include: 36, 216, 516, 4536, 64033513093126656, etc.
Lots of things: They are both multiples of 1, 2, 3, 4, 6, 8, 12 and 24. They are both even. They are both integers. They are both positive. They are both real numbers. They are both rational numbers. All of those things and many other things, they have in common.