11+1+1+3+5(we cant perform the operation by direct methods sine addid 6b numbers from this set of numbers ll always give even number)
You can make 24 4-digit numbers. 1111 2222 3333 4444 5555 6666 1234 2345 3456 1356 6543 5432 4321 1432 ok i give up!
21
(7777-6666)/1111 = 1 (4444+5555)/(9999/3333) = 3 8888/2222 = 4 4*3 + 1 =13
T
This is impossible. 21 is an odd number and all these digits are odd. Whenever you add 6 odd numbers together, the answer is always even!
You can make 24 4-digit numbers. 1111 2222 3333 4444 5555 6666 1234 2345 3456 1356 6543 5432 4321 1432 ok i give up!
21
5+5+5+1+1+4=21
(7777-6666)/1111 = 1 (4444+5555)/(9999/3333) = 3 8888/2222 = 4 4*3 + 1 =13
T
9915 1159 5555 9999 1111
9/3 + 9+ 5+ 3+ 1
This is impossible. 21 is an odd number and all these digits are odd. Whenever you add 6 odd numbers together, the answer is always even!
9/3+9+5+3+1=21
public static void main(String[] args) { for(int i=1;i<5;i++) { for(int j=1;j<5;j++) { System.out.print(i); } System.out.println(); } }
0.5555 = 5555/10000 = 1111/2000
1, 5, 11, 55, 101, 505, 1111, 5555.