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Q: What is the different combination of all 4 digit numbers between 1111 and 9999 that add up to the sum of 13?

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9^9 = 387420489 different digit combinations.

That would be the numbers in the form "32x" (where "x" can be any digit). In other words, ten numbers.

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.

There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.

use the digit 1234to make two different numbers

5,040

the diffrenece between two 3 digit numbers is a palindrome between 200 and 300. what are the numbers?

Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.Any multiple of 36 will do. Multiply 36 by different numbers, until you get a 5-digit number.

There are 9 1-digit numbers and 16-2 digit numbers. So a 5 digit combination is obtained as:Five 1-digit numbers and no 2-digit numbers: 126 combinationsThree 1-digit numbers and one 2-digit number: 1344 combinationsOne 1-digit numbers and two 2-digit numbers: 1080 combinationsThat makes a total of 2550 combinations. This scheme does not differentiate between {13, 24, 5} and {1, 2, 3, 4, 5}. Adjusting for that would complicate the calculation considerably and reduce the number of combinations.

5

There are 900 three-digit whole numbers between 1 and 1000

There are 900 three-digit numbers, all of which are between 99 and 3,000.

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