#include<stdio.h>
#include<conio.h>
void main()
{
int i,c,n; printf("Enter the number of terms you want which are divisible by 7");
scanf("%d",&n);
c=0;
for(i=7;;i+=7)
{
printf("\n %d ",i);
c++;
if(c==n)
break;
}
getch();
}
Chat with our AI personalities
There is an infinite number of numbers that are not divisible by seven!
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
There are 22 such numbers.
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
NO, 837 is not divisible by 2. Because it ends in 7, and 7 is a odd number. Only numbers that are even numbers can be divisible by 2.