#include<stdio.h>
#include<conio.h>
void main()
{
int i,c,n; printf("Enter the number of terms you want which are divisible by 7");
scanf("%d",&n);
c=0;
for(i=7;;i+=7)
{
printf("\n %d ",i);
c++;
if(c==n)
break;
}
getch();
}
There is an infinite number of numbers that are not divisible by seven!
Oh, dude, let's break it down. So, first, you gotta figure out how many numbers are divisible by 3, right? Then, do the same for 7. But, here's the kicker - you gotta remember to subtract the numbers divisible by both 3 and 7. It's like a math puzzle, but with numbers. So, like, get your calculator out and have fun with it.
There are 22 such numbers.
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
NO, 837 is not divisible by 2. Because it ends in 7, and 7 is a odd number. Only numbers that are even numbers can be divisible by 2.
Best way to work this out: find the highest number below 10,000 that is divisible by 7 (9,996) and divide that by 7 (1,428). 1,428 is the amount of one-, two-, three- and four-digit numbers divisible by 7. Now find the number of one-, two- and three-digit numbers divisible by 7 (which is 994/7 = 142) and subtract this number from 1,428, giving us 1,286.
all numbers are divisible by 7.
There is an infinite number of numbers that are not divisible by seven!
Oh, dude, let's break it down. So, first, you gotta figure out how many numbers are divisible by 3, right? Then, do the same for 7. But, here's the kicker - you gotta remember to subtract the numbers divisible by both 3 and 7. It's like a math puzzle, but with numbers. So, like, get your calculator out and have fun with it.
factors of 34 are: 1,2, 17 and 34. there are an infinite amount of numbers divisible by 34. they way you can find a number divisible by 34 is by multiplying 34 by any number. the answer you get is divisible by 34. example: 7*34=238 238/34=7 (238 is divisible by 34)
There are 14 numbers between 1 & 100 that are divisible by 7.
There are 22 such numbers.
Numbers that are divisible by both 6 and 7 must be divisible by the least common multiple of 6 and 7, which is 42. Therefore, the numbers divisible by both 6 and 7 are multiples of 42. This includes numbers like 42, 84, 126, and so on.
prime numbers between 0 -100 which are divisible by 7: 7
NO, 837 is not divisible by 2. Because it ends in 7, and 7 is a odd number. Only numbers that are even numbers can be divisible by 2.
There are a total of 14 numbers between 0 & 100 that are divisible by 7.
Any multiple of 7 is divisible by 7. The integers are of the form I = 7n for any integer n.The number 7 and all numbers that are multiples of 7.