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just divide the vector by its lenght. Square root of 4+9=square root of 13, so divide by that 2/Sqrt(13) -3/Sqrt(13)
The unit vector is a vector whose magnitude is 1.
It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.It is a vector whose magnitude is 1.
Yes, a unit vector can have negative component since a unit vector has same magnitude and direction as a negative unit vector. Here is the general work out of the problem: Let |v| be the norm of (v1, v2). Then, the unit vector is (v1/|v|, v2/|v|). Determine the "modulus" or the norm |(v1/|v|, v2/|v|)| to get 1, which is the new norm. If we determine the norm of |(-v1/|v|, -v2/|v|)|, we still have the same norm 1.
A signal is said to be orthonormal when two vector are perpendicular and having unit length.
A unit line segment would have vector <1/2,sqrt(3)/2>.