no the cannot
The shape you are describing is a trapezoid. A trapezoid has two pairs of parallel sides, with one pair longer than the other. It can have two acute angles and two obtuse angles, depending on the lengths of the sides. The acute angles are typically smaller than 90 degrees, while the obtuse angles are larger than 90 degrees.
80 has 5 factor pairs.
The sum of all the interior angles of a quadrilateral is 360 degrees. If it had more than three obtuse angles, then it would have all four angles greater than 90 degrees so that their sum would be greater than 360 degrees.
95 degrees.Supplementary angles are pairs of angles that add up to 180 degrees. So if we know that one is 10 degrees more than the other we can say that:Where x is equal to the supplement then,x + x + 10 = 180Therefore2x + 10 = 1802x = 180 - 102x = 170x = 85So the angle is 85 + 10 = 95 degrees (and its supplement is 85 degrees).
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Lone pairs reduce bond angles because they occupy more space than bonding pairs of electrons. This increased repulsion from the lone pairs pushes the bonding pairs closer together, resulting in smaller bond angles. Additionally, lone pairs are not involved in bonding interactions, so they exert a stronger repulsive force on adjacent bonding pairs, further distorting the geometry of the molecule.
Alright, honey, you've got yourself a trapezoid. It's got two acute angles and two obtuse angles, two pairs of parallel sides, and two pairs of equal sides. It's like the Beyoncé of quadrilaterals - fierce and fabulous.
Ordinarily, yes: one is acute (less than 90 degrees) and one is obtuse (more than 90 degrees), such that their sum is 180 degrees. The exception is if both angles are right angles (2 x 90 degrees).
because O has 2 non-bonding electron pairs. To add to this, when there are 2 non-bonding pairs, they become lone pairs which repulse the 2 hydrogen somewhat which changes the angle from 180 to 104.5.
The largest effect on a neighboring bond angle is typically exerted by lone pairs of electrons. Lone pairs occupy more space than bonding pairs, causing the bonds around them to compress and alter the angles between neighboring bonds. Additionally, the presence of electronegative atoms can also influence bond angles by exerting inductive effects, but the impact of lone pairs is generally more significant in distorting bond angles.
Lone pairs occupy more space than bond pairs because they are localized on a single atom and do not have to share their electron density with another atom. This results in a greater repulsive effect on surrounding electron pairs, leading to a more expanded spatial arrangement. Additionally, lone pairs are typically larger and more diffuse than bonding pairs, which are concentrated between two nuclei. As a result, the presence of lone pairs can alter molecular geometry and bond angles.
A lone pair of electrons occupies space around a central atom, which can repel the bonding pairs of electrons more strongly than bonding pairs repel each other. This repulsion alters the bond angles and can lead to a distortion in the molecular shape, resulting in geometries that differ from idealized forms. For example, in water (H₂O), the two lone pairs on oxygen push the hydrogen atoms closer together, creating a bent shape rather than a linear arrangement.
The two angles of a linear pair must add to 180 degrees. So if one is less than 90 degrees (acute) the other must be more than 90 degrees (obtuse).
No. They can only be exactly 180 degrees. By definition, a linear pair is a pair of two adjacent supplementary angles, so together they must form exactly 180 degrees.
No a pentagon has way more angles than a triangle does.
Angles less than 90 = actute Angles of 90 = right angle Angles more than 90 = obtuse Angles more than 180 = reflex
A parallelogram that isn't a rhombus, rectangle, or square has. Any polygon with more than 4 sides could also have.