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Q: Can one plane sometimes pass through three noncollinear points?

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Any Euclidean plane has infinitely many points.

Only one plane can pass through 3 non-collinear points.

If you're asking a question, then the answer is 'no'. If you're making a statement, then the statement is false. I can always lay a single plane down on any three points you choose. If your points are in the same straight line, then there an infinite number of other planes that your points all lie in. If they're not all in the same straight line, then there's only one plane.

Sometimes.

A plane figure has 2 dimensions (length & width$ & is represented by a flat surface. It takes 3 noncollinear points to make a plane. A solid figure has 3 dimensions. It not only has length & width but also depth. It takes 4 noncoplaner points to make space

Related questions

A plane

A plane. A circle can also pass through three non-co-linear points.

Any Euclidean plane has infinitely many points.

just one

Only one plane can pass through 3 non-collinear points.

3 or more

Three.

Three

No, A plane can be drawn through any 3 points. If the 3 points are collinear then they make a line and a plane can contain a line. If the points are noncollinear then they can be used to form the corners of a triangle; all points of a triangle are in the same plane.

Yes. You require three non-collinear points to uniquely define a plane!

1 line cause every plane contains atleast 3 or more noncollinear points

1, exactly 1 plane will

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