Only one plane can pass through 3 non-collinear points.
1 straight line. An infinite number of curved lines.
Any two points lie on the same line, since a line can be drawn through any two points.Three points that lie on the same line are described as being "collinear" points.
There is only one line (or line segment) that can be drawn between two distince points.
If you were to have 3 points on the same line, then you would actually not be determining a plane, because there are infinitely many planes that can intersect a given line. But if you have 3 points in the form of the points (or vertices) of a triangle, then you determine a plane in the sense that there is only one possible plane upon which that triangle can be drawn (not including a degenerate triangle, which is equivalent to a line).
secx is the inverse of cosx. secx=1/cosx. A secant is also a line drawn through the graph that touches two points on a function.
If you are talking about straight lines, the answer is NONE, because that is what noncollinear means. If curves are allowed, then the answer is infinitely many.
No, A plane can be drawn through any 3 points. If the 3 points are collinear then they make a line and a plane can contain a line. If the points are noncollinear then they can be used to form the corners of a triangle; all points of a triangle are in the same plane.
Between 2 distinct points, there are an infinite number of planes that can be drawn in 3 dimensions
Yes a plane can always be drawn three any three points, whether they are linear or not.
If the points are collinear, that means there's only one straight line. An infinite number of different planes can be drawn that contain one straight line.
Only one line can be drawn through eight points.
depend how many points are them
A line of best fit