answersLogoWhite

0

Can you combine y2 and 6y?

Updated: 4/28/2022
User Avatar

Wiki User

8y ago

Best Answer

If you are refering to y squared and 6y then no there is no way to combine them without knowing the value of y first

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Can you combine y2 and 6y?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

Multiply and simplify y-6 y-4?

(y-6)(y-4) y x y = y2 y x -4 = -4y y x -6 = -6y -4 x -6 = 24 y2 - 4y - 6y + 24 y2 - 10y + 24


What is Y if Y2 plus 6y-9 equals 0?

Y = 1.125 2Y + 6Y - 9 = 0 2Y + 6Y = 9 Y(2+6) = 9 8Y = 9 Y = 9/8 = 1 1/8 = 1.125 PROOF: 2(1.125) + 6(1.125) - 9 = 0 2.5 + 7.5 - 9 = 0 9 - 9 = 0


How do you FOIL a math problem witha binomial and a trinomial?

FOIL is an acronym standing for first, outside, inside, and last, which is a method for multiplying binomials For example: (a + b)(a + b) F (a + b)(a + b) = a2O (a + b)(a + b) = +abI (a + b)(a + b) = +abL (a + b)(a + b) = b2 a2 + ab + ab + b2 = a2 + 2ab + b2 *always remember to watch the signs. If you multiply -a times b you get -ab. Also, remember to add or subtract the coefficients (Coefficients are the numbers in front of the variables. If no number is seen, it is automatically a 1. The coefficient of -ab is -1 and the coefficient of ab is 1, thus ab + ab = 2ab). Multiplying binomials and trinomials is similar, but FOIL is not used. There are various methods used, here is one of them: Example 1 (x + 3)(x2 - 3x - 5) Step 1: Multiply x by the entire trinomial (x + 3)(x2 - 3x - 5) = x3(x + 3)(x2 - 3x - 5) = -3x2(x + 3)(x2 - 3x - 5) = -5x Step 2: Multiply 3 by the entire trinomial. Remember to keep the signs, or in other words, remember that 3 is positive. (x + 3)(x2 - 3x - 5) = +3x2(x + 3)(x2 - 3x - 5) = -9x(x + 3)(x2 - 3x - 5) = -15 The product looks like: x3 - 3x2 - 5x + 3x2 - 9x - 15 Step 3: Combine like terms or simplify x3 - 14x - 15 Remember that terms are ordered by the highest power to the lowest power. Example 2(2y - 3)(y2 + 6y + 10) Step 1: (2y - 3)(y2+ 6y + 10) = 2y3(2y - 3)(y2 + 6y + 10) = +12y2(2y - 3)(y2 + 6y + 10) = +20y Step 2: (2y - 3)(y2 + 6y + 10) = -3y2(2y - 3)(y2 + 6y + 10) = -18y(2y - 3)(y2 + 6y + 10) = -30 = 2y3 + 12y2 + 20y - 3y2 - 18y - 30Step 3: 2y3 + 9y2 + 2y - 30


What is 3x plus 6y plus 6x?

3x + 6y + 6x = 9x + 6y which can be factorised as 3(3x +2y)


What is the answer to 1 plus 6y?

That is the answer. If y is undefined, then 1+6y is as far as you can go.

Related questions

How do you solve y2-x-6y plus 6 equals 0 as a parabola equation?

y2-x-6y+6=0 y2-6y+6=x (y-3)2-3=x so y = 3+sqrt(x+3) or y = 3-sqrt(x+3)


What are the factors of y3-216?

(y - 6)(y2 + 6y + 36)


How do you factor the expression y2 plus 6y - 16?

(y + 8)(y - 2)


Multiply and simplify y-6 y-4?

(y-6)(y-4) y x y = y2 y x -4 = -4y y x -6 = -6y -4 x -6 = 24 y2 - 4y - 6y + 24 y2 - 10y + 24


What is the center and radius of x2 plus 6x plus y2-6y-232 equals 0?

As I understood your question: "What is the center and radius of: x2+6x+y2-6y-232=0?" First move 232 over to the right hand side to get: x2+6x+y2-6y = 232. Complete the square for both x's and y's: (x2 + 6x+ 9) + (y2 - 6y + 9) =232 + 9 + 9 Then rewrite: (x+3)2+(y-3)2=250 Now you can pick off the center --> (-3,3); and radius --> sqrt(250) = 5sqrt(10) approx. 15.8114


How do you factor 4x2 -y2-6y-9?

It is (2x +y + 3)*(2x - y - 3).


What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?

x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.


How do i factor the expression y2 plus 6y-16?

It is: (y+8)(y-2) and knowing how to use the quadratic equation formula does help.


How do you determine the center and radius of a circle with equation x2 plus y2 plus 10x minus 6y equals 0?

A circle with centre (x0, y0) and radius r has an equation of the form: (x - x0)2 + (y - yo)2 = r2 To get into this form, first reorder to separate the variables: x2 + y2 + 10x - 6y = x2 + 10x + y2 - 6y Second complete the square in each variable: x2 + 10x = (x + 5)2 - 25 y2 - 6y = (y - 3)2 - 9 Third substitute back in the equation and rearrange: (x + 5)2 - 25 + (y - 3)2 - 9 = 0 (x + 5)2 + (y - 3)2 = 34 The centre and radius of the circle can now be read from the equation: Centre = (-5, 3) Radius = sqrt(34)


How do you write the equation for each hyperbola in standard form when the equation is y2-3x2 plus 6x plus 6y equals 18?

y2-3x2+6x+6y= 18 is in standard form. The vertex form would be (y+3)2/24 - (x-1)2/8 = 1


How do you find the circumference of a circle set in the Cartesian plane whose equation is x squared plus y squared -4x -6y -3 equals 0?

x2 + y2 - 4x - 6y - 3 = 0 complete the squares: x2 - 4x + 4 + y2 - 6y + 9 - 4 - 9 - 3 = 0 simplify: (x - 2)2 + (y - 3)2 = 16 Therefore radius2 = 16 => radius = 4 and then circumference = 2*pi*r = 25.13 (approx)


What is the center and radius of a circle with an equation of x squared plus y squared - 10x plus 6y equals 47?

The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.