a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.
x5 = 33 1/3, solve for x. x is the fifth root of 33 1/3. If your scientific calculator doesn't have a specific key for nth. root, raise the number to the power 0.2 (that is, 1/5).
Since x and y are variables, the sum of 5x and 5y could be literally any number.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question with certainty. If the question is x*5 = 25 then the answer is x = 5. However, conventionally, x*5 would be written as 5x, not x5.
5x + 5y = 5(x+y)
Assuming that the question is find x in x5=1610; the answer is 4.378901
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.
x5 is an expression, not an equation nor an inequality. An expression cannot be solved.
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
11x5=55 !
512 x 5 = 2,560
5x-9Substitute 4 in for x5(4)-9=Solve.9-9=0the answer is zero.The answer is not zero you added when you were supposed to multiply so the real answer is 11.
5 times 5 equals 25.
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