(x + 3y)(x2 - 3xy + 9y2)
x3+27y3 = (x+3y) · (x2-3xy+9y2)
When the expression is broken down into its prime factors it is factored completely.
a3-4a = a(a2-4) when factored
27y3 + 125z3 = (3y + 5z)*(9y2 - 15yz + 25z2).
Fortunately, one of the three roots of 27y3 - 1 is really obvious, y = 1/3. Therefore we can pull (y - 1/3) out of the expression giving us:(y - 1/3)(27y2 + 9y +3).Using the quadratic formula on the second multiplicative expression gives:[-9 ± √(-243)]/54 = (-9 ± 9i√3)/54.So the complete, factored form of 27y3 - 1 is:(y - 1/3)[y - (9 + 9i√3)/54][y - (9 - 9i√3)/54].
If you mean: y2+5y+6 then it is (y+2)(y+3) when factored completely
A completely factored form is one which is composed of product of factors and can't be factorized further. Let us consider two examples: x2 - 4x + 4 is not a factored form because it can be factored as (x - 2)(x - 2). (x +1)(x2 - 4x + 4) is also not a factored form because x2 - 4x + 4 can be factored further as (x - 2)(x - 2). So, the completely factored form is (x + 1)(x - 2)(x - 2).
Completely Factored
-5
77r + 74r - 16 = 151r - 16 and that cannot be factored further.
urr momm