the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
The chance of rolling it each time is (1/6). So the chance of rolling it 4 times in a row is(1/6) x (1/6) x (1/6) x (1/6) = (1/1296) = 0.0007716 = 0.0772 % (rounded)The chance of rolling it each time is the same. It's not affected by what came before,since dice have no memory.
The experimental probability of anything cannot be answered without doing it, because that is what experimental probability is - the probability that results from conducting an experiment, a posteri. This is different than theoretical probability, which can be computed a priori. For instance, the theoretical probability of rolling an even number is 3 in 6, or 1 in 2, or 0.5, but the experimental probability changes every time you run the experiment.
202
Well, isn't that a delightful question! After 9009 comes 9010. Each number is like a little friend, patiently waiting its turn in line. Just keep adding one more each time, and you'll reach the next number in no time at all.
You have a 3.125% chance of not rolling an even number, because each time you roll a die you have a 50% chance of not rolling an even number, but each additional time you roll a die your chances of not rolling an even number the formula changes from 3/6 to 3/12 because the possibilities double but your chances of not rolling an even remain the same so eventually we end up with 3/96 because of rolling the die 6 times.
the chances of rolling a 2 each time during 1 set of 3 rolls is -1 in 216- sets. i believe the formula is: 1 in 6 - the chance of rolling a"2" then multiply the chances for each separate roll 1/6 x 1/6 x 1/6 = 1/216
0.25 ( P = 0.5 each time)
Not Sure
10/3
Approximately 1/1120 * You have a 27.777% chance of rolling either a six or an eight on the first roll. * You have a 13.888% chance of rolling the same thing as the first roll. * You have a 13.888% chance of doing it again. * You have a 16.666% chance of rolling a seven. To find total probability in this situation, you multiply all of your chances together. .27777 x .13888 x .13888 x .16666 = 0.000892886 = .0892886% =1/1119.964 You may just be finding this out now, but casinos have known it for a long time. The casinos simply make their payouts less than the probability and they can't lose. While I recognize that your question deals with the probablity of an event recurring, for the average gambler, there is another way to look at this. Dice have no memory. Therefore, each time you roll them, the probability of rolling a given number remains the same. Each time you roll the dice, the chances of rolling a 6 before a 7 is 6 to 5 against you. The same odds apply to rolling an 8 before a 7.
On an unweighted die, regardless of how many successes you've had, your chance of rolling a five will be one in six. The chance of you rolling a die 16 times and getting a five each time would be 1/616, or 0.00000000000035447042. The chance of rolling a die 16 times and getting the same number (regardless of what that number is) each time, would be 1/615, or 0.00000000000212682249 Regardless of how slim that chance is though, your chance on the next roll will still be 1/6. However, if this is meant as a "real world" question, then your chances of rolling the same number so many times in a row is so low that at that point, your odds would be much higher of there being something odd with the die, or with your experiment. At that point, it would be sensible to say that the odds are very good of rolling another 5, regardless of the math, as there seems to be another factor affecting your outcome.
You can't, can you? The smallest number that you can roll with four dice is four, that is, a 'one' on each of the four dice.
Something just happened. As something would have to happen to make nothing happen, the probability of something else happening is approximately 100%.If you have a more specific definition of something, probability can be calculated by [# of events] divided by [# of possible outcomes].For example:> The chances of rolling a 1 or a 2 on a 6-sided diecalculated by 2[either rolling a 1 or rolling a 2] divided by 6[either rolling a 1 and rolling a 2 and rolling a 3 and rolling a 4 and rolling a 5 and rolling a 6]2/6 = 1/3 = One in Three ~ 33.333%> The chances of something happening (the Time variable is irrelevant) calculated by ∞[infinite number of somethings] divided by ∞[infinite possible occurences of something]∞/∞ = 1 = 100%
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
50% chance
Every number on a number cube is a whole number. (A whole number is a number without a fraction or decimal) So the probability of rolling a whole number on a number cube one time would be 6/6 or 1.