Octal = 52746757
Binary = 101010111100110111101111
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Convert each group of 4 bits into one hexadecimal digit. 1010 is "A" in hexadecimal, so this particular number is "AA".
I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).I assume the number is in binary. Separate the binary number from the right, 4 digits at a time: 1011 1011. Then convert each group of four binary digits to hexadecimal. In this case, 1011 is B, so the answer is 0xBB (the prefix 0x is often used to indicate hexadecimal).
221122: Binary = 1000100001000100100010 Octal = 10410442 Decimal = 2232610
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
You could first convert it to binary, and then to hexadecimal. Because octal and hexadecimal bases are both powers of two, the conversion between those bases and binary is quite easy. To go from octal to binary, take each digit in the number, and convert it to three binary digits: 5 -> 101 3 -> 011 2 -> 010 4 -> 100 So the binary version of the number is: 101 011 011 010 100 In order to convert to hexadecimal, your number of digits needs to be divisible by four (as 24 = 16). To get that, we need to add a digit, which will be a zero as our leftmost digit: 0101 0110 1101 0100 Now we can convert each of those sets of four binary digits into single hexadecimal digits, giving us our final answer: 9AD8