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Q: Determine the event space for rolling a sum of 11 with two dice How many elements are in the event space?

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There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.

The sample space for rolling a die is [1, 2, 3, 4, 5, 6] and the sample space for tossing a coin is [heads, tails].

Lets first start by defining some terms:Probability (P) in statistics is defined as the chance of an event occurring.Probability experiment is a chance process that leads to results called outcomes.An outcome is the result of a single trial of a probability experiment.A sample set is the set of all possible outcomes of a probability experiment.An event consists of a set of outcomes of a probability experiment. An event can be one outcome or more than one outcome. The event can be anything from flipping a coin, to rolling a die, to picking a card.The probability of any event (E) is:(# of outcomes in E) / (total # of outcomes in sample space)For example: Find the probability a die is rolled and you get a 4?We know that there are 6 possibilities when rolling a die. We can either rolled a 1, or a 2, or a 3, or a 4, or a 5, or a 6.Using the equation above:P(rolling a 4)= 1/6The event in this case is rolling a 4.

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There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.

Related questions

Three.

216

Only one is.

The even numbers that can be rolled on a single die are 2,4, and 6 so the number of elements in the event space is 3. X={2,4,6}.

When you roll two dice, a 7 may occur as (1,6),(2,5),(3,4),(4,3),(5,2),(6,1) There are 6 elements in the event space.

It is rolling 1 or 2.

There are 6 elements; 1,2,3,4,5,&6.

12

For a regular number die, the event space is {1, 2, 3, 4, 5, 6}.

There are 5 elements in the event space if you roll a sum of 8 with 2 dice; 2,6 & 6,2 & 3,4 & 4,3 & 4,4.

One.

Two.

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