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What is a probability of an event?
Lets first start by defining some terms:Probability (P) in statistics is defined as the chance of an event occurring.Probability experiment is a chance process that leads to results called outcomes.An outcome is the result of a single trial of a probability experiment.A sample set is the set of all possible outcomes of a probability experiment.An event consists of a set of outcomes of a probability experiment. An event can be one outcome or more than one outcome. The event can be anything from flipping a coin, to rolling a die, to picking a card.The probability of any event (E) is:(# of outcomes in E) / (total # of outcomes in sample space)For example: Find the probability a die is rolled and you get a 4?We know that there are 6 possibilities when rolling a die. We can either rolled a 1, or a 2, or a 3, or a 4, or a 5, or a 6.Using the equation above:P(rolling a 4)= 1/6The event in this case is rolling a 4.
What is the ratio of the number of equally likely outcomes in an event to the total number of possible outcomes?
You find the total number of outcomes by adding the first part of the odds to the second part of the odds. For example: 1:1 The total number of outcomes would be 2. To find the ratio of equally likely outcomes to the total number, find the number of outcomes, and put it on the left of the semicolon. Then put the total number on the right side. For the same example: (outcomes)->1:2<-(total)
Two coins are flipped and a die is rolled how many possible outcomes are there?
Each coin can land in two ways.The die has 6 possible outcomes.So there are 2 x 2 x 6 = 24 possible outcomes for the whole experiment.Note that I am assuming the coins can be told apart - say the first coin and 2nd coin and that H and then T is different that T and then H. If not, then there are only be three outcomes for the coins-- 2 heads, 1 head or no heads and the total number of outcomes would be 3 X 6 = 18.
How many possible outcomes are there in 4 different football games with 8 total teams?
To calculate the total number of possible outcomes in 4 different football games with 8 total teams, you would multiply the number of teams in each game together. In this case, there are 8 teams in the first game, 7 teams in the second game (as one team has already been used), 6 teams in the third game, and 5 teams in the fourth game. Therefore, the total number of possible outcomes would be 8 x 7 x 6 x 5 = 1,680 possible outcomes.
If you have 10 football matches with 3 outcomes win lose and draw how many different combinations are there?
IF YOU HAVE ONE GAME, YOU HAVE A POSIBILITY OF 3 OUTCOMES, IF YOU HAVE 2 GAMES IT GO'S UP TO 9 POSIBILE OUTCOMES. FIRST ANSWER 1X3=3 SECOND IS 3X3=9 FOR 10 GAMES IT IS 3X3 TEN TIMES 3X3X3X3X3X3X3X3X3X3=59,049 POSSIBLE COMBINATIONS (I THINK)HA HA
How many possible outcomes are in the sample space for the event first toss a coin then shoot a basket?
4
How many possible outcomes ar in the sample space for the event first toss a coin then shoot a basket?
4
How many possible outcomes are in the sample space for the event first roll a die and then shoot a basket?
There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.
How many outcomes are in the sample space for the event first to toss a coin and then to shoot a basket?
4
If one event has impossible outcomes and a second event has no possible outcomes after the first event has occurred then there are m times n total possible outcomes for the two events?
M=0 n=0 m*n=0
What is a probability of an event?
Lets first start by defining some terms:Probability (P) in statistics is defined as the chance of an event occurring.Probability experiment is a chance process that leads to results called outcomes.An outcome is the result of a single trial of a probability experiment.A sample set is the set of all possible outcomes of a probability experiment.An event consists of a set of outcomes of a probability experiment. An event can be one outcome or more than one outcome. The event can be anything from flipping a coin, to rolling a die, to picking a card.The probability of any event (E) is:(# of outcomes in E) / (total # of outcomes in sample space)For example: Find the probability a die is rolled and you get a 4?We know that there are 6 possibilities when rolling a die. We can either rolled a 1, or a 2, or a 3, or a 4, or a 5, or a 6.Using the equation above:P(rolling a 4)= 1/6The event in this case is rolling a 4.
A coin is tossed 2 times what are the number of possible outcomes?
There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.
What is the ratio of the number of equally likely outcomes in an event to the total number of possible outcomes?
You find the total number of outcomes by adding the first part of the odds to the second part of the odds. For example: 1:1 The total number of outcomes would be 2. To find the ratio of equally likely outcomes to the total number, find the number of outcomes, and put it on the left of the semicolon. Then put the total number on the right side. For the same example: (outcomes)->1:2<-(total)
What is the independent and dependent event for pulling two marbles out of a bag?
The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.
How do you draw a tree diagram to determine the number of outcomes?
Well you start with the first event, how many possibilities, draw a line down for each one, and state what event occurred. I.e. a heads or tails of a coin. Then from each of these outcomes, draw the possible outcomes from each of the first events reflecting the second events, i.e. HH, HT, TH, TT. Third outcome (third flip of a coin) would look like this. HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
How many possible outcomes are there of choosing 1 number from the first 6 positive whole numbers?
Six.
How many outcomes are there when a die is rolled twice?
6 possible numbers to land on the first time, 6 possible numbers to land on the second time, 6x6=36
