Of course not! The solution to some equations could represent the area under a curve, or the volume of some shape, or the rate of change in something.
A=S2... Where A = area, and S = length of one side.
The two solutions are coincident.
It often helps to isolate the radical, and then square both sides. Beware of extraneous solutions - the new equation may have solutions that are not part of the solutions of the original equation, so you definitely need to check any purported solutions with the original equation.
It often helps to square both sides of the equation (or raise to some other power, such as to the power 3, if it's a cubic root).Please note that doing this may introduce additional solutions, which are not part of the original equation. When you square an equation (or raise it to some other power), you need to check whether any solutions you eventually get are also solutions of the original equation.
1) When solving radical equations, it is often convenient to square both sides of the equation. 2) When doing this, extraneous solutions may be introduced - the new equation may have solutions that are not solutions of the original equation. Here is a simple example (without radicals): The equation x = 5 has exactly one solution (if you replace x with 5, the equation is true, for other values, it isn't). If you square both sides, you get: x2 = 25 which also has the solution x = 5. However, it also has the extraneous solution x = -5, which is not a solution to the original equation.
A=S2... Where A = area, and S = length of one side.
Technically,no. A radical equation has a radical (Square root) in it, and has two solutions because the square root can be positive or negative.
An equation can be determine to have no solution or infinitely many solutions by using the square rule.
The two solutions are coincident.
P_square=4L where L is the length of the side of the square.
Yes. Quite often, if you don't, you'll lose solutions. That is, the transformed equation - after taking square roots - will have less solutions than the original equation.
The equation is based on formula (x - h)square / A square + (y-k)square / B square = 1. To apply to the above ellipse the equation would be similar to (x- 0) square/ 14 square + (2014 - 0) square / 16 square.
Two cases in which this can typically happen (there are others as well) are: 1. The equation includes a square. Example: x2 = 25; the solutions are 5 and -5. 2. The equation includes an absolute value. Example: |x| = 10; the solutions are 10 and -10.
The answer is indeterminate. There are many solutions for this.
It often helps to isolate the radical, and then square both sides. Beware of extraneous solutions - the new equation may have solutions that are not part of the solutions of the original equation, so you definitely need to check any purported solutions with the original equation.
It is A=s^2 area = length of side times itself If you have square with side length 3, area is 3x3, 9 square units
It often helps to square both sides of the equation (or raise to some other power, such as to the power 3, if it's a cubic root).Please note that doing this may introduce additional solutions, which are not part of the original equation. When you square an equation (or raise it to some other power), you need to check whether any solutions you eventually get are also solutions of the original equation.