Not necessarily.
All one can say about "any rectangle" is that the opposite triangles are of equal areas.... that does not mean that adjacent ones do.
So, in a rectangle ABCD, with diagonals which cross at E
ABE = CDE
and
ADE = BCE
but
ABE may not be equal to ADE
Chat with our AI personalities
no
We know that diagonals of parallelogram bisect each other. Therefore, O is the mid-point of AC and BD. BO is the median in ΔABC. Therefore, it will divide it into two triangles of equal areas. Area (ΔAOB) = Area (ΔBOC) ... (1) In ΔBCD, CO is the median. Area (ΔBOC) = Area (ΔCOD) ... (2) Similarly, Area (ΔCOD) = Area (ΔAOD) ... (3) From equations (1), (2), and (3), we obtain Area (ΔAOB) = Area (ΔBOC) = Area (ΔCOD) = Area (ΔAOD) Therefore, it is evident that the diagonals of a parallelogram divide it into four triangles of equal area.
Triangles (four of) and a square.One square as base and four triangles as sides.
Triangular. the base is square, with four other triangular faces.
The formula for a square pyramid is one square attached to four triangles which meet at a point.There are other formulae for the surface area or for the volume.