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it depens if the isosceles triangle is a right triangle or not

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Q: Does the Pythagorean theorem work on isosceles triangles?
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Does Pythagorean Theorem work for triangles that don't have a 90 degree angle?

It does not; if there is no 90 degree angle there is no hypotenuse.


Does pythagoras' theorem work for all triangles?

no only right triangles


What is a non-example of a Pythagorean theorem?

for what values the pytagoreag dose not work


Area of isosceles tiangle?

The formula is: Area = base * height. With an isosceles triangle, two of the angles are congruent and their opposite sides are congruent. There is one remaining angle (that will be referred to as the top angle) and its opposite side (the base). You will probably have to drop a perpendicular line from the top angle to the base. This will bisect the base into two equal parts. Also, you now have two congruent right triangles. It depends on what you know with this triangle in order to find its height and/or base. However, use the Pythagorean Theorem and I'm sure you can work it out.


Why does the Pythagorean theorem work on only right triangles?

There is a Pythagorean theorem that actually works for every triangle. Its just that for right triangles it can be simplified to A2+B2=C2 due to the properties of cosines. The law of cosines states that for a triangle with sides A, B, and C, and angles a, b, and c (with side C being opposite angle c), C2 = A2 + B2 - (2 x A x B x cos c). This formula will work for any triangle. Now imagine that we are talking about a right triangle, with side C the hypotenuse (just like in the classic Pythagorean theorem) and angle c the right angle. The cosine of a 90 degree angle is 0, which means that the part in bold would completely drop out of the equation, leaving us with A2+B2=C2 . The cosine of any other angle possible on a triangle would result in some other number, making A2+B2=C2 not work.