answersLogoWhite

0

This depends on how accurate an estimate is required. If your answer need only be whole numbers, then 0.69 is slightly larger than 2/3 which is 0.66 = you could estimate 14 - which is 2/3 of 21. -- Alternatively, if your answer ought to be to one decimal place then you could say that it is nearly 70% and multiply 21 by 0.7 and get 14.7

User Avatar

Wiki User

17y ago

What else can I help you with?

Related Questions

What is 069?

069 = 69


What is the equivalent fraction of 21 over 27?

it is that this website does not have estimating with percents STUPID webste.


What is 45 X 60?

The answer to that is 2700. If your estimating, the answer will be 3000. Hope that helped!


What is the answer of estimating the quotient in 4471 and 7?

4000 x 8 = 32000


What is 483.62 times 29.77 estimating?

480 x 30 = 14400


What does 56 times 34 by estimating?

60 x 30 = 1800


What is pokedex number 069 in Pokemon emerald?

bellsprout is #069


What is 21 x 21?

21 x 21 = 441


What is 21 x 21 x 21?

9261


What does x equal in the equation 437 (21 plus x)(21 - x)?

To solve for ( x ) in the equation ( 437(21 + x)(21 - x) ), we can first simplify the expression using the difference of squares: ( (21 + x)(21 - x) = 21^2 - x^2 ). This gives us ( 437(441 - x^2) = 0 ). Setting ( 441 - x^2 = 0 ) leads to ( x^2 = 441 ), resulting in ( x = 21 ) or ( x = -21 ).


What is the answer to 35 divided by 535.6 with estimating?

0.0653


What is the ratio of the sum of two numbers whose product is 21 to their difference?

Two specific cases of pairs of numbers whose product is 21 are: 1 x 21 and 3 x 7. The ratio of their sum to their difference is: 1 x 21 ... (21+1):(21 - 1) = 22:20 = 11 : 10, and 3 x 7 ... (3+7):(7-3) = 10:4 = 5 : 2. To find a general formula, let the larger number be x and the smaller be 21/x. Their sum is x + 21/x = (x^2 +21)/x Their difference is x - 21/x = (x^2 -21)/x Ratio of sum to difference is [(x^2+21)/x] / [(x^2-21)/x] = [(x^2+21)/x] * [x/(x^2-21)] = (x^2+21)/(x^2-21) Check: This formula produces the results found above.