Two specific cases of pairs of numbers whose product is 21 are: 1 x 21 and 3 x 7.
The ratio of their sum to their difference is:
1 x 21 ... (21+1):(21 - 1) = 22:20 = 11 : 10, and
3 x 7 ... (3+7):(7-3) = 10:4 = 5 : 2.
To find a general formula, let the larger number be x and the smaller be 21/x.
Their sum is x + 21/x = (x^2 +21)/x
Their difference is x - 21/x = (x^2 -21)/x
Ratio of sum to difference is [(x^2+21)/x] / [(x^2-21)/x]
= [(x^2+21)/x] * [x/(x^2-21)]
= (x^2+21)/(x^2-21)
Check: This formula produces the results found above.
10 and 3
24,25,26
22 and 26
=The Two numbers are 41 and 13.=
They are 16 and 18
-76 and 76 whose product is -5776.
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
11
-12
-5 * 5 = -25
17 and 53
12 x 2 = 24 12 - 2 = 10 The two numbers are therefore 2 and 12.
Numbers whose product is one is called multiplicative inverses.
4 and 19 4 x 19 = 76 19 - 4 = 15
two prime numbers whose product is 141 = 3 & 47
3 and 7 are prime numbers whose product is 21.
Any two numbers whose product is '1' are each others' reciprocals.