The factor pairs of 20 are: 20,1 / 10,2 / 5,4
1x6, 2x3
Factor pairs of 42 are 1 x 42, 2 x 21, 3 x 14, and 6 x 7.
1 x 58 = 58 2 x 29 = 58 Therefore, factor pairs = 1 and 58, 2 and 29.
I usually start from the bottom - is 2 a factor, yes indeed. Then start over. Is 2 a factor, yes. Start over. Is 2 a factor, yes. Is 2 a factor, no. Is 3 a factor, no. is 4 a factor, no. Done.2, 2, 2, 5
Explaining how to find all factors pairs of 40 is easy. All you have to do is find which whole numbers 40 can be divided into.
1x40, 2x20, 4x10, 5x8 are all the factor pairs of 40.
The factor pairs of 20 are: 20,1 / 10,2 / 5,4
The factor pairs for 38 are (1, 19) and (2, 38).
The factor pairs of 26 are: 1 × 26 2 × 13
Apart from [1,201], [3,67] is the only other factor pair. Since both 3 and 67 are prime numbers, you know you won't be able to find any more factor pairs.
From the rules of divisibility, we know that 40 is divisible by 1, 2, 4 and 5. Divide those numbers into 40 to get the rest. (40,1)(20,2)(10,4)(8,5)
53,1
1,3,149,447
164,182,241,4
1,81,3,27,9
They are:165,155,333,515,11