Factors come in pairs. If you know one factor, divide it into the number. The answer will be another factor.
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.
because if you divide 40 by 1,2,4,and5 you will get the answer (and what about 8, 10, 20, and 40 ? are they nothing but chopped liver ?)
4 and 6 6 and 8 Any time the two numbers have a common factor, their LCM will be less than the product because the common factor contributes to the LCM fewer times than it contributes to the product.
If you include negative numbers, the list is infinite.
Factors come in pairs. If you know one factor, divide it into the number. The answer will be another factor.
Between 35 and 40, 36 has the most factor pairs.
Explaining how to find all factors pairs of 40 is easy. All you have to do is find which whole numbers 40 can be divided into.
Apart from [1,201], [3,67] is the only other factor pair. Since both 3 and 67 are prime numbers, you know you won't be able to find any more factor pairs.
From the rules of divisibility, we know that 40 is divisible by 1, 2, 4 and 5. Divide those numbers into 40 to get the rest. (40,1)(20,2)(10,4)(8,5)
Divide by two. 40 and 1 20 and 2 10 and 4 5 and 8
The factor pairs of 168 are the pairs of numbers that can be multiplied together to give the product 168. These pairs include (1, 168), (2, 84), (3, 56), (4, 42), (6, 28), (7, 24), (8, 21), and (12, 14). Factors are numbers that divide evenly into a given number, and in the case of 168, these factor pairs represent all the possible combinations of factors that multiply to 168.
Factors are divisors. If you know the divisibility rules, you know that 80 is divisible by 1, 2, 4, 5 and 8. If you divide 80 by those numbers, you find the other half of the factor pairs.
Well, just multiply numbers that equal 86. I'll say them. 1,2, 43 and 86.
1 and 8 2 and 4 They're the only numbers that divide evenly into 8 with no remainder.
The long but fool-proof way is to find the complete prime factorisation of the number. Then group all the factors into pairs, rejecting any that cannot be paired. The product of the numbers that are left is the largest square factor.
The factor pairs of 1295 are (1295,1)(259,5)(185,7)(37,35) None of them are consecutive. 35 and 37 are consecutive odd numbers.