The tessellating polygons must meet at a point. At that point, the sum of the interior angles of the polygons must 360 degrees - the sum of angles around any point. Therefore, each interior angle must divide 360 evenly. The interior angles of regular polygons with 7 or more sides lie in the range (120, 180) degrees and so cannot divide 360.
No, they will not fit together, you will also need a square with sides equal in length to the sides of the octagon.
They are known as regular polygons.
Yes, the corresponding sides of two similar regular polygons must have equal lengths. This is because both the polygons are similar, which means that since they are also polygons, they must have equal lengths.
All regular polygons with an even number of sides. Irregular polygons with an odd number of sides can have parallel sides. There are also non polygonal shapes that can have parallel sides.
Not all polygons are regular by definition. An irregular polygon may have non-congruent sides or non congruent angles or both. A regular polygon will always have both congruent sides and angles.
Most regular polygons will not - by themselves. In fact, of the regular polygons, only a triangle, square and hexagon will. No other regular polygon will create a regular tessellation. However, for polygons with any number of sides, there are irregular versions that can tessellate.
Some can, but not all. For example, rhombi, rhomboids, oblongs, and isosceles triangles can tessellate; however, most irregular polygons cannot. * * * * * True, but an incomplete answer. All triangles and quadrilaterals, whether regular or irregular, will tessellate. No regular pentagon will tessellate but (as of 2016), there are 15 irregular pentagons which will tessellate. There are 3 convex hexagons, (regular and 2 irregular) which will tessellate. No polygon with 7 or more sides, even if it is regular, will tessellate.
No. Equilateral triangles will tessellate and a triangle has 3 sides, which is an odd number.
No. Equilateral triangles will tessellate and a triangle has 3 sides, which is an odd number.
Shapes tessellate to fit around an interior angle. They also tessellate because they are regular polygons; non-regular polygons cannot tessellate. * * * * * Not correct. All triangles and quadrilaterals will tessellate, whether regular or irregular. Contrary to the above answer, a regular pentagon will not tessellate but there are 14 different irregular pentagons which will tessellate (the last was discovered in 2015). Three convex hexagons will do so as well. No polygon of 7 or more sides will tessellate - whether they are regular (contrary to the above answer) or irregular.
No, they will not fit together, you will also need a square with sides equal in length to the sides of the octagon.
You cannot tessellate convex polygons with 7 or more sides.
The only regular polygons which will tessellate are those with 3, 4 or 6 sides. But all irregular triangles, all irregular quadrilaterals, 15 classes of irregular convex pentagons and 3 classes of irregular convex hexagons will tessellate. In addition, there are concave polygons with different numbers of sides which will also tessellate.
There are non-regular polygons with a wide range of sides which will tessellate.
There is no simple way.All triangles will tessellate. All quadrilaterals will tessellate There are 15 classes of convex pentagons (the latest discovered in 2015) which will tessellate. Regular hexagons will tessellate. In addition, there are 3 classes of irregular convex hexagons which will tessellate. No convex polygon with 7 or more sides will tessellate.In addition, there are concave polygons, and non-polygons which will tessellate.
No convex polygon with 7 or more sides will tessellate.
All triangles will tessellate. All quadrilaterals will tessellate There are 15 classes of convex pentagons (the latest discovered in 2015) which will tessellate. Regular hexagons will tessellate. In addition, there are 3 classes of irregular convex hexagons which will tessellate. No convex polygon with 7 or more sides will tessellate.